9. b--para 10c
10. b--para 10d
A deviation of 40 kHz represents 100-percent modulation; therefore, an 80-
percent modulation will cause a 32-kHz (40 kHz x 80% = 32 kHz) deviation.
11. b--para 11h, i; Attached Memorandum, para 1-1
Channel width = 92.2 MHz - 92.1 MHz = 0.1 MHz, or 100 kHz
Guard band = 2 x 10 kHz = 20 kHz
Frequency swing = 100 kHz - 20 kHz = 80 kHz
12. c--para 11h(2), table I
Effective bandwidth (MI = 5) = 16 fA = 16 x 10 kHz = 160 kHz
Effective bandwidth (MI = 15) = 38 fA = 38 x 10 kHz = 380 kHz
13. c--para 11b(2), table I
fs-fc = 97.475 MHz - 97.400 MHz
= 0.075 MHz, or 75 kHz
Effective bandwidth = 2 x 75 kHz = 150 kHz = 50 fA
Table I shows that an effective bandwidth of 50 fA results from the
production of 25 sidebands with an MI of 20.
14. c--para 12d(6), (7)
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