18. Since the output of the divider shown in figure 4-2 is 100 kHz, what is the
reason for developing the 900-kHz frequency?
a. To bias mixer stage Q1
b. To lock transistor Q4 at 100 kHz
c. To establish a reference frequency for divider Q2
d. To heterodyne with the input for the development of the 100-kHz output
19. Although the discriminator used in figure 4-3 employs semiconductor diodes,
it functions exactly the same as the electron-tube type that is called a
a. balanced modulator discriminator.
b. double-tuned discriminator.
c. pulse discriminator.
d. phase discriminator.
20. If a small dc voltage is applied to the base of Q1 in figure 4-3, either a
frequency error or a defective component exists in the transmitter. The frequency
error that probably exists is the one generated by
a. oscillator Q2.
b. oscillator QS.
c. audio stage Q1.
d. driver Q5.
CHECK YOUR ANSWERS WITH LESSON 4 SOLUTION SHEET PAGES 54 and 55.
HOLD ALL TEXTS AND MATERIALS FOR USE WITH EXAMINATION AND SIG 324.
323 L4
46
Previous Page
