2. d--para 62b
3. b--para 62d, e
IIF = Gc x ERF
= 4,000 x 10-6 x 0.28 x 320 x 10-6
= 0.36 microampere
EIF = IIF x RL
= 0.36 microampere x 2,000 ohms
= 720 microvolts
4. a--para 63a(2)
Taking the extreme case, it can be seen that if the input signal is 88
MHz, an image frequency of 108 MHz will be obtained when the IF is 10 MHz. That
is, 88 MHz + (2 x 10 MHz) = 108 MHz. Hence, an IF of 10.7 MHz will insure that the
image frequency will be outside of the frequency band.
5. b--para 63b
6. a--para 63e
7. b--para 63e(l)
8. d--para 63e(l)
9. b--para 64-66
10. c--para 64-66
11. c--para 62d, e; 64
The conversion gain obtainable from a mixer depends on the conversion
transconductance and the circuit alterations to counteract noise.
The diode
provides no conversion gain and the noise introduced in the triode and pentogrid
mixers limit their conversion gains.
Since the pentode has an extremely high
conversion transconductance and permits high voltage gain, it provides the greatest
conversion gain.
12. a--para 65
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